Ohms law examples4/5/2024 The resistance of the wire from the Current-Voltage graph is, R=1.00 ohm Thus the resistivity of the material of the wire is 3.92 ×10 -7 ohm.m Final result Thus from the equation-2 we get the resistivity of the material of the wire is, Thus, the Resistance from the graph, R= ∆V/∆I = 0.5/0.5 = 1.00 ohm Calculation of resistivity of the wire Now, from the graph, change in current, ∆I = AB = 0.5 ampĬorresponding change in voltage, ∆V = BC = 0.5 volt The inverse of the I-V graph gives the resistance of the wire. If we plot the Current as a function of voltage with the help of above data then we will get a straight line passing through origin.Ĭurrent versus Voltage graph Calculations Calculation of resistance from graph Current versus Voltage graph (Ohm’s Law graph) We also need to plot I-V graph to confirm the experimental value of R. Now we got the calculated value of the resistance of the wire is R= 1.02 ohm. Thus, the voltage across the wire is proportional to the current through the wire. So, we can see that in each observation the voltage to current ratio is almost same. The least count of Voltmeter = Smallest division of voltmeter = 0.05 Volt No. The least count of Ammeter = Smallest division of Ammeter = 0.05 ampere
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